诺4【根号2-m/6】与6【根号2m-3/4】是同类项二次根式,则m=

问题描述:

诺4【根号2-m/6】与6【根号2m-3/4】是同类项二次根式,则m=

同次二次根式,说明被开方数相同
(2-m)/6=(2m-3)/4
2(2-m)=3(2m-3)
4-2m=6m-9
m=13/8