已知m^2-n^2=4mn,求代数式(m^4+n^4)/m^2 .n^2的值
问题描述:
已知m^2-n^2=4mn,求代数式(m^4+n^4)/m^2 .n^2的值
答
M/N-N/M=4
(M/N-N/M)^2=16
(M/N)^2+(N/M)^2-2=16
(M^4+N^4)/M^2*N^2=(M/N)^2+(N/M)^2=14