若tana+1/tana=4,则sin2a

问题描述:

若tana+1/tana=4,则sin2a

tanA+1/tanA
=sinA/cosA+cosA/sinA
=sin²A/sinAcosA+cos²A/sinAcosA
=1/sinAcosA=4
sin2A=2sinAcosA=2*1/4=1/2