一道英文的物理题
问题描述：
一道英文的物理题
When a proton captures an electron,a photon with an
energy of 13.6 eV is emitted.What is the frequency of this
photon?Does it lie in,above,or below the visible range?
答
当一个质子捕获一个电子时,会发射出一个具有13.6电子伏能量的光子,请问这个光子的频率是多少?它是否在可见光频率范围之内?之上?之下?
E=hv=hc/lambda,E=13.6eV=2.178X10-18 J,h=6.626 × 10 -34 J·s,=> v=3.288X10 15 Hz,lambda=91.2nm,which is smaller than lower limit of visible range.The frequency is above visible range