已知：△ABC∽△A1B1C1,△A1B1C1∽△A2B2C2.求证：△ABC∽△A2B2C2
问题描述：
已知：△ABC∽△A1B1C1,△A1B1C1∽△A2B2C2.求证：△ABC∽△A2B2C2
不能用角相等,只能用对应边的比相等
答
因为△ABC∽△A1B1C1,所以,AB/A1B1=AC/A1C1=BC/B1C1=K1,所以,AB=K1A1C1,AC=K1A1C1,BC=K1B1C1；因为△A1B1C1∽△A2B2C2,所以,A1B1/A2B2=A1C1/A2C2=B1C1/B2C2=K2,所以,A1B1=K2A2B2,A1C1=K2A2C2,B1C1=K2B2C2.所以,AB=K1...