化简:1/6a-1/2(a+1)+1/3(a-1)=

问题描述:

化简:1/6a-1/2(a+1)+1/3(a-1)=

1/6a-1/2(a+1)+1/3(a-1)
=[(a+1)(a-1)-3a(a-1)+2a(a+1)]/6a(a+1)(a-1)
=(a²-1-3a²+3+2a²+2)/6a(a+1)(a-1)
=4/6a(a²-1)
=2/3(a³-a)