[log3（4）+log根下3（2）][log2(9)+log4(根3)]
问题描述：
[log3（4）+log根下3（2）][log2(9)+log4(根3)]
答
[log₃4+log‹√₃›2][log₂9+log₄√3]
原式=[log₃4+log₃4][log₂9+log₂3^(1/4)]
=(4log₃2)[(9/4)log₂3]=9(log₃2)(1/log₃2)=9
答
[log3（4）+log根下3（2）][log2(9)+log4(根3)]
=[2log3（2）+2log3（2）][2log2(3)+1/4log2(3)]
=4log3（2)*9/4log2(3)
=4*9/4*log3*log2(3)
=9