log4^8+log4^2-(1/4)^0 等于多少?

问题描述:

log4^8+log4^2-(1/4)^0 等于多少?

log4^8+log4^2-(1/4)^0
=log4^(8*2)-1
=log4^16-1
=log4^(4^2)-1
=2log4^4-1
=2-1
=1