f(x)=e^ax/x-1求导.
问题描述:
f(x)=e^ax/x-1求导.
答
f'(x)=[(e^ax)a(x-1)-e^ax]/(x-1)^2=(e^ax)(ax-a-1)/(x-1)^2
f(x)=e^ax/x-1求导.
f'(x)=[(e^ax)a(x-1)-e^ax]/(x-1)^2=(e^ax)(ax-a-1)/(x-1)^2