[(240-48)/x]+[48/(x-10)]=240//(x-4)
问题描述：
[(240-48)/x]+[48/(x-10)]=240//(x-4)
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答
[(240-48)/x]+[48/(x-10)]=240//(x-4)
[192(x-10)+48x]/x(x-10)=240/(x-4)
240x(x-10)=(x-4)(240x-1920)
x(x-10)=(x-4)(x-8)
x²-10x=x²-12x+32
2x=32
x=16