从算式1/2+1/4+1/6+1/12+1/24+1/48中去掉两个分数,使余下的分数之和等于1,则去掉的两个分数之和是多少?

问题描述:

从算式1/2+1/4+1/6+1/12+1/24+1/48中去掉两个分数,使余下的分数之和等于1,则去掉的两个分数之和是多少?

去掉的两个分数之和是:1/2+1/4+1/6+1/12+1/24+1/48-1=3/48