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问题描述：
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数学人气：963 ℃时间：2020-01-29 08:02:29
优质解答
tan(α+π/4)=(1+tana)/(1-tana)=3+2√2
tana=√2/2
(1-cos2α)/sin2α
=(1-(1-2sin^2a))/2sinacosa
=sins/cosa
=tana=√2/2
tana=√2/2
(1-cos2α)/sin2α
=(1-(1-2sin^2a))/2sinacosa
=sins/cosa
=tana=√2/2
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答
tan(α+π/4)=(1+tana)/(1-tana)=3+2√2
tana=√2/2
(1-cos2α)/sin2α
=(1-(1-2sin^2a))/2sinacosa
=sins/cosa
=tana=√2/2