lim(x→1)xlnx/(x-1)(x+1)=?
问题描述:
lim(x→1)xlnx/(x-1)(x+1)=?
答
洛必达法则:
lim(x→1)xlnx/(x-1)(x+1)
=lim(x→1)(xlnx)’/(x^2-1)'
=lim(x→1)( lnx +1)/2x
=1/2