计算:(4ab3-8a2b2)÷4ab+(2a+b)(2a-b)

问题描述:

计算:(4ab3-8a2b2)÷4ab+(2a+b)(2a-b)

原式=4ab3÷4ab-8a2b2÷4ab+(4a2-b2),
=b2-2ab+4a2-b2
=4a2-2ab.