x+1分之2x=1 x-2分之x-x^2-4分之1=1 x+3分之5=x分之2 x-2分之6=x+3分之x -1
问题描述：
x+1分之2x=1 x-2分之x-x^2-4分之1=1 x+3分之5=x分之2 x-2分之6=x+3分之x -1
答
2x/(x+1)=1, 2x=x+1, x=1.
x/(x-2)-1/(x²-4)=1,
x/(x-2)-1/[(x+2)(x-2)]=1,
x(x+2)-1=(x+2)(x-2),
x²+2x-1=x²-4
2x=-3
x=-3/2=-1.5
5/(x+3)=2/x, 5x=2x+6, 3x=6, x=2
6/(x-2)=(x-1)/(x+3)
(x-2)(x-1)=6x+18
x²-3x+2=6x+18
x²-9x-16=0
x²=[9±√(81+64)]/2=[9±√(145)]/2
答
(1)2x/(x+1)=12x=x+1x=1(2) x/(x-2)-1/(x²-4)=1x(x+2)-1=x²-4x²+2x-1=x²-42x=-3x=-3/2(3) 5/(x+3)=2/x5x=2(x+3)5x=2x+6x=2(4) 6/(x-2)=(x-1)/(x+3)6(x-2)=(x-1)(x+2)6x-12=x²+x-2x²-5...