计算1/(x-1)+1/((x-1)(x-2))+1/((x-2)(x-3))+.+1/((x-99)(x-100))
问题描述:
计算1/(x-1)+1/((x-1)(x-2))+1/((x-2)(x-3))+.+1/((x-99)(x-100))
答案是1/(x-100)
答
1/[(x-1)(x-2)]=1/(x-2)-1/(x-1).
依此类推,原式=1/(x-1)+1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2).+1/(x-100)-1/(x-99)=1/(x-100)