已知函数f(x)=mx^2+3(m_2)x_1在区间(-无穷,3】上单调减函数,则实数m的取值范围
问题描述:
已知函数f(x)=mx^2+3(m_2)x_1在区间(-无穷,3】上单调减函数,则实数m的取值范围
答
0
答
等等
答
f(x)=mx^2+3(m-2)x-1
=m(x+3(m-2)/2m)^2-9(m-2)^2/(4m)-1
m>0,...1)
3(m-2)/2m