若x-7的绝对值等于0,y+2的绝对值等于0,z的绝对值等于4且xyz大于0,求2x+2y-yz的值

问题描述:

若x-7的绝对值等于0,y+2的绝对值等于0,z的绝对值等于4且xyz大于0,求2x+2y-yz的值

|x-7|=0,∴ x=7;
|y+2|=0,∴ y=-2;
|z|=4,且xyz>0,∴ z=-4;
则:2x+2y-yz=2×7 + 2×(-2) - (-2)×(-4) = 14 - 4 - 8 = 2