[12÷﹙χ-6﹚×3⅓-9]+1900=1981 1

问题描述:

[12÷﹙χ-6﹚×3⅓-9]+1900=1981 1

[12÷﹙χ-6﹚×3⅓-9]+1900=1981
12÷(x-6)×3⅓-9=81
12÷(x-6)×3⅓=90
12÷(x-6)=90
90×(x-6)=12
90x-540=12
90x=552
x=552/90
x=31/5
x=6.2