lim*[ln(1+3X)]/sin4X {X->0}求极限

分类: 作业答案 • 2021-12-20 12:29:28

问题描述：

lim*[ln(1+3X)]/sin4X {X->0}求极限
lim*[ln(1+3X)]/sin4X {X->0} 求极限

答

Lim[ln(1+3X)]/sin4X
x->0
=
Lim{[ln(1+3X)]/3X}*[4X/sin4X]*(3/4)
x->0
=
Lim{[ln(1+3X)]/3X}*Lim[4X/sin4X]*(3/4)
x->0.x->0
=1*1*3/4
=3/4