第一题 (X+1)(X平方+1)(X4方+1)(X-1=?第二题 若n平方+n-1=0则n3方+n平方-n+2008=?

1:(x+1)(x-1)(x^2+1)(x^4+1)=(x^2-1)(x^2+1)(x^4+1)=x^8-1
2:n^3+n^2-n+2008=n(n^2+n-1)+2008=0+2008=2008

第一题：（X的4次方-1）
第二题：2008

(X+1)(X平方+1)(X4方+1)(X-1）
=(X+1)(X-1）)(X平方+1)(X4方+1)
=（X平方-1)(X平方+1)(X4方+1)
=(X4方-1)(X4方+1)
=X8方-1
n3方+n平方-n+2008
=n（n²+n-1）+2008
n平方+n-1=0
原式=n（0）+2008=2008

1. x的8次方-1
2. 2008

(X+1)(x^2+1)(X^4+1)(X-1)=
(X+1)(x-1)(x^2+1)(X^4+1)=
(x^2-1)(x^2+1)(X^4+1)=
(x^4-1)(x^4+1)=
x^8-1
n^3+n^2-n+2008
=n(n^2+n-1)+2008
=n*0+2008
=2008

1.=(x^2-1)(x^2+1)(x^4+1)=(x^4-1)(x^4+1)=x^8-1
2.原式=n（n^2+n-1）+2008=0+2008=2008