您的位置: 首页  >  作业答案  >  其他  >  若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

分类: 作业答案 • 2021-12-20 09:49:27
问题描述：

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

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