用因式分解法解方程:2(y-1)²+y=1

问题描述:

用因式分解法解方程:2(y-1)²+y=1

(y-1)(2(y-1)+1)=0
(y-1)(2y-1)=0
y=1或y=1/2

2(y-1)²+y-1=0
2(y-1)²+(y-1)=0
(y-1)(2y-2+1)=0
(y-1)(2y-1)=0
y=1,y=1/2

2(y-1)²+y=1
2(y-1)²+(y-1)=0
(y-1)(2y-2+1)=0
(y-1)(2y-1)=0
y-1=0或2y-1=0
y1=1 y2=1/2