求y=1+ x乘e的xy次方的微分.
问题描述：
求y=1+ x乘e的xy次方的微分.
答
y=1+x[e^(xy)] y'=e^(xy)+x[e^(xy)]*(y+xy') y'=e^(xy)+xy[e^(xy)]+(x^2)[e^(xy)] y'{1-(x^2)[e^(xy)]}=(1+xy)[e^(xy)] y'={(1+xy)[e^(xy)]}/{1-(x^2)[e^(xy)]} dy=y'dx=【{(1+xy)[e^(xy)]}/{1-(x^2)[e^(xy)]}】dx