已知A=1/2,B=-2,C=4,求1/2A^2B-[3/2A^2B-(3ABC-A^2C0-4A^2C]-3ABC的值

分类: 作业答案 • 2021-12-20 08:14:21

问题描述：

答

(1/2)A^2B-[(3/2)A^2B-(3ABC-A^2C)-4A^2C]-3ABC
= (1/2)A^2B-(3/2)A^2B+3ABC-A^2C+4A^2C-3ABC
= -A^2B+3A^2C
= A^2(-B+3C)
= (1/2)^2*(2+3*4)
= 7/2