x=2008,y=2006,求〔2x〔x^2y-xy^2〕+xy〔2xy-x^2〕〕÷x^2y的值.
问题描述:
x=2008,y=2006,求〔2x〔x^2y-xy^2〕+xy〔2xy-x^2〕〕÷x^2y的值.
答
原式=(2x³y-2x²y²+2x²y²-x³y)÷x²y
=x³y÷x²y
=x
=2008