请先化简(x-3/2x-x+3/x)÷9-x²/x,再选取一个既使原式有意义,又是你喜欢的数带入求值.

(2x/x-3-x/x+3)×x^2-9/x,
={[2x(x+3)-x(x-3)]/(x+3)(x-3)}×[(x^2-9)/x]
=[2x^2+6x-x^2+3x)/(x^2-9)]×[(x^2-9)/x]
=(x^2+9x)/x
=x+9
=1+9
=10

[(x-3)/2x-(x+3)/x]÷[(9-x²)/x]
=[(x-3)-2(x+3)]/(2x)×[x/(3-x)(3+x)]
=[(-x-9)/(2x)]×[x/(3-x)(3+x)]
=(x+9)/[2(x-3)(x+3)]
当x=1时,原式=10/(-16)=-5/8