1/3(3y-10-7y/2)-1/2(2y-2y+2/3)=y/2-1 求y=( )/是分数线

问题描述:

1/3(3y-10-7y/2)-1/2(2y-2y+2/3)=y/2-1 求y=( )
/是分数线

1/3(3y-10-7y/2)-1/2(2y-2y+2/3)=y/2-1
2(3y-10-7y/2)-3(2y-2y+2/3)=6(y/2-1)
6y-10+7y-6y+2y+2=3y-6
6y=2
y=1/3