arctanx+arctan1/x在区间[-π/2 π/2 ]的定积分

问题描述:

arctanx+arctan1/x在区间[-π/2 π/2 ]的定积分

arctanx+arctan1/x=π/2
∫(-π/2→π/2)(π/2)dx
=π^2/2
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