(x+3y)/﹙x²-y²﹚-(x+2y)/(x²-y²)+﹙2x-3y﹚/﹙x²-Y²﹚
问题描述:
(x+3y)/﹙x²-y²﹚-(x+2y)/(x²-y²)+﹙2x-3y﹚/﹙x²-Y²﹚
答
原式=y/﹙x²-y²﹚+﹙2x-3y﹚/﹙x²-Y²﹚=2﹙x-y﹚/﹙x²-Y²﹚=2/(x+y)
(x+3y)/﹙x²-y²﹚-(x+2y)/(x²-y²)+﹙2x-3y﹚/﹙x²-Y²﹚
原式=y/﹙x²-y²﹚+﹙2x-3y﹚/﹙x²-Y²﹚=2﹙x-y﹚/﹙x²-Y²﹚=2/(x+y)