小明解方程2x-3/5+1=x+a/2时,由于粗心大意,在去分母时,方程左边的1没有乘以10,由此求的解为x=0,试求a的值,并正确地求出方程的解.
问题描述：
小明解方程2x-3/5+1=x+a/2时,由于粗心大意,在去分母时,方程左边的1没有乘以10,由此求的解为x=0,试求a的值,并正确地求出方程的解.
答
2(2x - 3) + 1 = 5(x + a)
x = 0 代入上式得:
2×(-3) + 1 = 5a
5a = -5
a = -1
(2x - 3)/5 + 1 = (x - 1)/2
2(2x - 3) + 10 = 5(x -1)
4x - 6 + 10 = 5x - 5
x = -6 + 10 + 5
x = 9
答
把x=0代入20x-6+1=10x+5a得 a=-1
答
2(2x - 3) + 1 = 5(x + a)
把 x = 0 代入得:
2×(-3) + 1 = 5a
5a = -5
a = -1
(2x - 3)/5 + 1 = (x - 1)/2
2(2x - 3) + 10 = 5(x -1)
4x - 6 + 10 = 5x - 5
x = -6 + 10 + 5
x = 9