24[1/8(3x-1+x²)-2/3(x³-2x²+3)-x}

问题描述:

24[1/8(3x-1+x²)-2/3(x³-2x²+3)-x}

24[1/8(3x-1+x²)-2/3(x³-2x²+3)-x]=24*1/8(3x-1+x²)-24*2/3(x³-2x²+3)-24*x=3(3x-1+x²)-16(x³-2x²+3)-24x=9x-3+3x²-16x³+32x²-48-24x=-16x³+3x...