·设集合A={x/(x-3)(x-a),A∈R} ,B={x/(x-4)(x-1)=0}求AuB,AnB
问题描述:
·设集合A={x/(x-3)(x-a),A∈R} ,B={x/(x-4)(x-1)=0}求AuB,AnB
答
①当a=3时,
AuB={3,1,4},AnB={空集}
②当a=4时,
AuB={3,1,4},AnB={4}
③当a=1时,
AuB={3,1,4},AnB={1}
④当a≠1,3,4时,
A={3,a},B={4,1}
所以,AuB={3,1,4,a},AnB=空集