(2008-x)(2006-x)=2007,求(2008-x)^2+(2006-x)^2的值+(2006-x)^2平方在外面哦
问题描述:
(2008-x)(2006-x)=2007,求(2008-x)^2+(2006-x)^2的值
+(2006-x)^2平方在外面哦
答
(2008-x)^2+(2006-x)^2
=[(2008-x)^2+(2006-x)^2-2(2008-x)(2006-x)]+2(2008-x)(2006-x)
=[(2008-x)-(2006-x)]^2+2(2008-x)(2006-x)
=2^2+2(2008-x)(2006-x)
=4+2*2007
=4018
答
(2008-x)^2+(2006-x)^2
=[(2008-x)-(2006-x)]^2+2(2008-x)(2006-x)
=2^2+2*2007
=4+4014
=4018