√5-√6-√20+√2/3+√9/5=
问题描述：
√5-√6-√20+√2/3+√9/5=
答
原式可化为：根 5-根6-2根5+根6/3+3根5/5=-2根5/5-2根6/3.
答
√5-√6-√20+√2/3+√9/5=
=√5-√6- 2√5+(√6)/3+(3√5)/5
=-(2√5)/5 - (2√6)/3