解{(x+2y)(x-2y)-(x-2y)的平方+8y(x+y)}除4x 分解因式(x+y)的平方-3(x+y)

问题描述:

解{(x+2y)(x-2y)-(x-2y)的平方+8y(x+y)}除4x 分解因式(x+y)的平方-3(x+y)

{(x+2y)(x-2y)-(x-2y)²+8y(x+y)}÷4x
={(x²-4y²-x²+4xy-4y²+8xy+8y²}÷4x
=(12xy)÷4x
=3y