(4a²-b)²-(4a²+b)²等于多少?
问题描述:
(4a²-b)²-(4a²+b)²等于多少?
答
(4a²-b)²-(4a²+b)²=[(4a²-b)+(4a²+b)][(4a²-b)-(4a²+b)]=8a²*(-2b)=-16a²b运用a²-b²=(a+b)(a-b)
(4a²-b)²-(4a²+b)²等于多少?
(4a²-b)²-(4a²+b)²=[(4a²-b)+(4a²+b)][(4a²-b)-(4a²+b)]=8a²*(-2b)=-16a²b运用a²-b²=(a+b)(a-b)