设根号2等于a,根号3等于b,用含a,b式子表示根号0.54.

问题描述:

设根号2等于a,根号3等于b,用含a,b式子表示根号0.54.

根号0.54
=根号(54/100)
=根号54/10
=根号(2×3×3×3)/10
=根号2×(根号3)³/10
=ab³/10

3ab/10

√0.54 = √(6×0.09)
=0.3*√6
=0.3*√2*√3
=0.3ab