2cosa-sina=0,则tan(a+4分之π)=

问题描述:

2cosa-sina=0,则tan(a+4分之π)=

2cosa-sina=0
sina=2cosa
tana=sina/cosa=2
tan(a+π/4)
=(tana+tanπ/4)/(1-tanatanπ/4)
=(tana+1)/(1-tana)
=(2+1)/(1-2)
=-3