求反函数 有答案 要步骤 看能看明白才给分y=(1-X)/(1+X) y=(ax+b)/(cx+d) y=2sin3X (X绝对值小于等于-π/6） y=(2^x)/(2^x+1

y=(1-x)/(1+x)
x=(1-y)/(1+y)
(1+y)x=1-y
x+xy=1-y
xy+y=1-x
(x+1)y=1-x
y=(1-x)/(x+1)
y=(ax+b)/(cx+d)
x=(ay+b)/(cy+d)
x(cy+d)=ay+b
cxy+dx=ay+b
cxy-ay=b-dx
y(cx-a)=b-dx
y=(b-dx)/(cx-a)
y=2sin3x (x绝对值小于等于-π/6)
x=2sin3y
x/2= sin3y
arcsin(x/2)=3y
y=arcsin(x/2)/3(y绝对值小于等于-π/6)
y=(2^x)/(2^x+1)
x=(2^y)/(2^y+1)
x(2^y+1)=2^y
x2^y+x=2^y
x2^y-2^y=-x
2^y(x-1)=-x
2^y=-x/(x-1)
y=log2(x/(1-x)