计算:(a-b)^2n+1(b-a)^2n÷(b-a)^2n+2
问题描述:
计算:(a-b)^2n+1(b-a)^2n÷(b-a)^2n+2
答
=-(b-a)^2n+1+2n-2n-2
=(a-b)^2n-1
答
题应该为:(a-b)^(2n+1)*(b-a)^2n÷(b-a)^(2n+2)
=-(b-a)^(2n+1)*(b-a)^2n÷(b-a)^(2n+2)
=-(b-a)^(2n-1)
答
(a-b)^(2n+1)*(b-a)^2n÷(b-a)^2n+2
=(a-b)^(2n+1)*(b-a)^(2n-2n-2)
=(a-b)^(2n+1)*(b-a)^(-2)
=(a-b)^(2n+1)*[-(a-b)^(-2)]
=-(a-b)^(2n+1-2)
=-(a-b)^(2n-1)