函数y=根号下（x^2+1）+1 (x
问题描述：
函数y=根号下（x^2+1）+1 (x
答
y=√（x^2+1）+1>2
=> (y-1)^2 =x^2+1
=>x^2=(y-1)^2-1
=>x=-√[(y-1)^2-1]
=>x=-√[(y-1)^2-1]
=>y=-√[(x-1)^2-1] (x>2)