(3x+2y)(4x-5y)+(2x)²×(3y)³÷36x²y+5xy,其中x=1,y=﹣1
问题描述:
(3x+2y)(4x-5y)+(2x)²×(3y)³÷36x²y+5xy,其中x=1,y=﹣1
答
(3x+2y)(4x-5y)+(2x)²×(3y)³÷36x²y+5xy
=12x²-7xy-10y²+3y²+5xy
=12x²-2xy-7y²
其中x=1,y=﹣1
原式=12+2-7=7