对任意实数ab定义min =aa≤b;min =bagt;b设函数fx=-x+3gx=log2x则函数hx=min{fx

问题描述:

对任意实数ab定义min =aa≤b;min =bagt;b设函数fx=-x+3gx=log2x则函数hx=min{fx

画两个函数的图可知h(x)取最大值时是f(x)与g(x)的交点的值.则-x+3=log2x解得x=2.最大值是1.查看原帖>>