计算x2+2x+4x2+4x+4÷x3−83x+6÷1/x2−4.

问题描述:

计算

x2+2x+4
x2+4x+4
÷
x3−8
3x+6
÷
1
x2−4
.

原式=

x2+2x+4
(x+2)2
÷
(x−2)(x2+2x+4)
3(x+2)
÷
1
(x+2)(x−2)

=
x2+2x+4
(x+2)2
3(x+2)
(x−2)(x2+2x+4)
•(x+2)(x-2)
=3.