计算x2+2x+4x2+4x+4÷x3−83x+6÷1/x2−4.
问题描述:
计算
÷
x2+2x+4
x2+4x+4
÷
x3−8 3x+6
. 1
x2−4
答
原式=
÷
x2+2x+4 (x+2)2
÷(x−2)(x2+2x+4) 3(x+2)
1 (x+2)(x−2)
=
•
x2+2x+4 (x+2)2
•(x+2)(x-2)3(x+2) (x−2)(x2+2x+4)
=3.