求10000~99999之间的奇数回文数的个数?

问题描述:

求10000~99999之间的奇数回文数的个数?

10001,30003,50005,70007,90009
改变中间那位从0到9
11011,31013,51015,71017,91019
.
.
.
19091,39093,59095,79097,99099
所以有10*5*10=500个