设x^2n=3,求(1/3x^3n)·[4(x^5)^n]急

问题描述:

设x^2n=3,求(1/3x^3n)·[4(x^5)^n]急

答案是4,先约分啊,4(x^5)^n可以化成4(x^5n)或
4x^[(2n+3n)]这样3x^3n与4x^[(2n+3n)])约分,它们都有x^3n,这样就得4