分解因式:x2-2x-2y2+4y-xy=_.
问题描述:
分解因式:x2-2x-2y2+4y-xy=______.
答
原式=(x2-xy-2y2)+(-2x+4y),
=(x-2y)(x+y)-2(x-2y),
=(x-2y)(x+y-2).
故答案为:(x-2y)(x+y-2).