已知α为锐角,tanα=1/3,求cosα+sinα/cosα-sinα

问题描述:

已知α为锐角,tanα=1/3,求cosα+sinα/cosα-sinα

原式分子分母同除cosx,
得:原式=(1+tanx)/(1-tanx)
=(1+1/3)/(1-1/3)
=2
祝你开心!希望能帮到你。。。

cosα+sinα/cosα-sinα
=1+tanα/1-tanα
=(1+1/3)/(1-1/3)
=2

cosα+sinα/cosα-sinα
分子分母同除以cosα
=(1+tanα)/(1-tanα)
=(1+1/3)/(1-1/3)
=2

(cosα+sinα)/(cosα-sinα)
分子分母同除以cosα:
= (1+tanα)/(1-tanα)
= (1+1/3)/(1-1/3)
=2