怎么将2x-3xy-2y+3x+4y-2因式分解
问题描述：
怎么将2x-3xy-2y+3x+4y-2因式分解
答
=2x^2+3x(1-y)-(2y^2-4y+2) =2x^2-3x(y-1)-2(y-1)^2 =(2x+y-1)(x-2y+2)
怎么将2x-3xy-2y+3x+4y-2因式分解
=2x^2+3x(1-y)-(2y^2-4y+2) =2x^2-3x(y-1)-2(y-1)^2 =(2x+y-1)(x-2y+2)